document.write( "Question 206009: What is the value of k so that the line (2+k)x + (2-k)y = 15 has a slope of 3/2? \n" ); document.write( "
Algebra.Com's Answer #155579 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The goal here is to first get the standard equation \"Ax%2BBy=C\" into the slope-intercept equation \"y=mx%2Bb\"\r
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\n" ); document.write( "\n" ); document.write( "\"%282%2Bk%29x+%2B+%282-k%29y+=+15\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"%282-k%29y+=+15-%282%2Bk%29x\" Subtract \"%282%2Bk%29x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"%282-k%29y+=+-%282%2Bk%29x%2B15\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%28-%282%2Bk%29x%2B15%29%2F%282-k%29\" Divide both sides by \"2-k\" to isolate \"y\".\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+-%28%282%2Bk%29%2F%282-k%29%29x%2B15%2F%282-k%29\" Break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "Now the equation is in the form \"y=mx%2Bb\" where the slope is \"m=-%282%2Bk%29%2F%282-k%29\" and the y-intercept is \"b=15%2F%282-k%29\"\r
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\n" ); document.write( "\n" ); document.write( "Because we want the slope to be \"3%2F2\", this means that \"m=3%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "So the next step is to solve \"3%2F2=-%282%2Bk%29%2F%282-k%29\" for 'k'. I'll let you do that.
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