document.write( "Question 205972: Make x the subject of the following:\r
\n" ); document.write( "\n" ); document.write( "y = 2 - x² / 2x² + 3
\n" ); document.write( "y = √2x- 3y (the sign before 2x is of square root)
\n" ); document.write( "1/a + 1/√x = y\r
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Algebra.Com's Answer #155557 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Make x the subject of the following:
\n" ); document.write( "y = 2 - x² / 2x² + 3
\n" ); document.write( "y(2x^2+3) = 2-x^2
\n" ); document.write( "2x^2y+x^2 = 2-3y
\n" ); document.write( "x^2(2y+1) = 2-3y
\n" ); document.write( "x^2 = (2-3y)/(2y+1)
\n" ); document.write( "-------------------------------------
\n" ); document.write( "y = √2x- 3y (the sign before 2x is of square root)
\n" ); document.write( "sqrt(2x) = y + 3y
\n" ); document.write( "2x = (4y)^2
\n" ); document.write( "x = 8y^2
\n" ); document.write( "------------------------------
\n" ); document.write( "1/a + 1/√x = y
\n" ); document.write( "1/sqrt(x) = y-(1/a)
\n" ); document.write( "1/sqrt(x) = (ay-1)/a
\n" ); document.write( "sqrt(x) = a/(ay-1)
\n" ); document.write( "x = [a/(ay-1)]^2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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