document.write( "Question 205979: There are four problems I need help with. \r
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document.write( "Solve algebraically.\r
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document.write( "1. cuberoot(x)-5=3
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document.write( "2.x^3/2=27
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document.write( "3.3/4=1-3x-2/x+1\r
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document.write( "Sove algebraically and check your potential solutions.
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document.write( "4.square root of x+2-x=0 \n" );
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Algebra.Com's Answer #155555 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve algebraically. \n" ); document.write( "1. cuberoot(x)-5=3 \n" ); document.write( "cubrt(x) = 8 \n" ); document.write( "x = 8^3 \n" ); document.write( "x = 512 \n" ); document.write( "----------------------\r \n" ); document.write( "\n" ); document.write( "2.x^(3/2)=27 \n" ); document.write( "Raise both sides to the (2/3) power to get: \n" ); document.write( "x = 27^(2/3) \n" ); document.write( "x = 3^2 \n" ); document.write( "x = 9 \n" ); document.write( "-----------------------\r \n" ); document.write( "\n" ); document.write( "3.3/4=1-3x-2/x+1 \n" ); document.write( "Comment: Include parenthese so fractions can be distinguised. \n" ); document.write( "---------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Sove algebraically and check your potential solutions. \n" ); document.write( "4.square root of x+2-x=0 \n" ); document.write( "sqrt(x+2) = x \n" ); document.write( "x+2 = x^2 \n" ); document.write( "x^2-x-2 = 0 \n" ); document.write( "(x-2)(x+1) = 0 \n" ); document.write( "x = 2 or x = -1 \n" ); document.write( "--- \n" ); document.write( "Checking: \n" ); document.write( "If x = 2 you get sqrt(0)=2 \n" ); document.write( "false so x=2 is not a solution \n" ); document.write( "------------ \n" ); document.write( "If x = -1 you get sqrt(1) = -1 \n" ); document.write( "false so x = -1 is not a solution \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |