document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=205954>Question 205954</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of a rectangular playground is 160 sq.m. and its perimeter is 52sq.m. what is the length and width of the playground?\r<BR>\n" );
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document.write( "please help...please also show the solution so i will know how to solve...thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155552 by </B><A HREF=/tutors/aboutme.mpl?userid=RAY100><B>RAY100(1637)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=RAY100><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155552\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area  = Length  *  Width,,A=LW = 160,,,,,,,or  L=160/W<BR>\n" );
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document.write( "Perimeter = 2(L+W) ,,,,,P=2L +2W =52,,,,subst  from  above<BR>\n" );
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document.write( "52= 2(160/W) +2W,,,,,multiply  thru  by  \"W\"<BR>\n" );
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document.write( "52W = 320 +2W^2<BR>\n" );
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document.write( "2w^2 -52W +320 =0,,,,,divide  by  2<BR>\n" );
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document.write( "W^2 -26W +160 =0<BR>\n" );
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document.write( "solve  for  W,,,using  Quadratic  Formula<BR>\n" );
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document.write( "a=1,,,,b=(-26),,,c=160<BR>\n" );
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document.write( "W=[ -(-26) +/-sqrt{ (-26)^2 -4 (1)(160)}]/2(1)<BR>\n" );
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document.write( "W= [26 +/- sqrt{676 -640}]/2<BR>\n" );
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document.write( "W= [26 +/- 6]/2<BR>\n" );
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document.write( "w= 10,,16<BR>\n" );
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document.write( "solving  for  L=160/W,,,L= 16,10<BR>\n" );
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document.write( "Therefore,,,W=10,,,L=16,,,,,,by  convention  W less  than L<BR>\n" );
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document.write( "Check,  A= 10*16=160,,,ok<BR>\n" );
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document.write( "P=2(10+16)=2*26 = 52,,,,,ok<BR>\n" );
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