document.write( "Question 205977: Bob wants to have concrete driveway in fron of his house. The driveway will measure 58 2/3 feet long and 18 1/2 feet wide; and will be 3/4 foot thick. How many cubic yards of cement will be needed for the driveway? Round your answer to the nearest cubic yard. \n" ); document.write( "
Algebra.Com's Answer #155546 by Alan3354(69443)\"\" \"About 
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Bob wants to have concrete driveway in fron of his house. The driveway will measure 58 2/3 feet long and 18 1/2 feet wide; and will be 3/4 foot thick. How many cubic yards of cement will be needed for the driveway? Round your answer to the nearest cubic yard.
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\n" ); document.write( "58 2/3 ft = 704 inches
\n" ); document.write( "18 1/2 ft = 222 inches
\n" ); document.write( "3/4 foot = 9 inches
\n" ); document.write( "V = 704*222*9 cubic inches
\n" ); document.write( "V = 1406592 in^3
\n" ); document.write( "V = 1406592/1728 ft^3
\n" ); document.write( "V = 814 cubic ft
\n" ); document.write( "V = 814/27 cubic yr
\n" ); document.write( "V = ~ 30 cubic yards
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\n" ); document.write( "Suppose the problem was in metric units.
\n" ); document.write( "1.788 meters
\n" ); document.write( "5.63 meters
\n" ); document.write( "0.2286 meters
\n" ); document.write( "V = 17.88*5.63*0.2286 cubic meters
\n" ); document.write( "V = 23 m^3
\n" ); document.write( "Much simpler. \n" ); document.write( "
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