document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=205965>Question 205965</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the 2001st number in the sequence: 2, 5, 8, 11,...? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155538 by </B><A HREF=/tutors/aboutme.mpl?userid=dyakobovitch><B>dyakobovitch(40)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dyakobovitch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155538\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are dealing with an arithemetic sequence with d=r, a(sub1)=2, and n=2001.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Your formula for finding the a(subn) term of an arithmetic sequence is \r<BR>\n" );
document.write( "\n" );
document.write( "a(subn)=a(sub1) + (n-1)d = 2 + (2001-1)(3) = 6002.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "I hope this help! Feel free to leave comments or concerns. -- David </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );