document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28542>Question 28542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A square fountain has an area of 16 square feet.  A flower garden is planted around the fountain.  If the garden extends 8 feet beyond the fountain, what is the area of the garden. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15552 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15552\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have a circle inside a circle.<BR>\n" );
document.write( "The inner circle has area =(pi)r^2=16<BR>\n" );
document.write( "r^2=16/(pi)<BR>\n" );
document.write( "r=4/sqrt(pi)<BR>\n" );
document.write( "The outer circle has radius \"8+[4/sqrt(pi)]<BR>\n" );
document.write( "The whole outer circle has area (pi)[8+4/sqrt pi]^2<BR>\n" );
document.write( "=pi[64+(64/sqrt pi) + (16/pi)]=64pi +64 sqrt pi + 16<BR>\n" );
document.write( "Subtract the inner area from the whole area to get the <BR>\n" );
document.write( "area of the garden, as follows:<BR>\n" );
document.write( "64pi+64sqrt(pi)+16 - 16 = 64pi+64sqrt(pi) is the area of the garden.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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