document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=205923>Question 205923</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Q(x)=5x2-6x+3; find Q(1/2)\r<BR>\n" );
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document.write( "Determine the domain of the function.<BR>\n" );
document.write( "P(x)=x2-2x-10<BR>\n" );
document.write( "     ---------<BR>\n" );
document.write( "     5x2+10x<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155505 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155505\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Q(x)=5x2-6x+3; find Q(1/2)<BR>\n" );
document.write( "Q(1/2) = 5(1/2)^2 - 6(1/2) + 3<BR>\n" );
document.write( "= (5/4) - 3 + 3<BR>\n" );
document.write( "= 5/4<BR>\n" );
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document.write( "Determine the domain of the function.<BR>\n" );
document.write( "P(x)=x^2-2x-10<BR>\n" );
document.write( "     ---------<BR>\n" );
document.write( "     5x^2+10x<BR>\n" );
document.write( "------------------------<BR>\n" );
document.write( "Factor to get:<BR>\n" );
document.write( "P(x) = [x^2-2x-10)/[5x(x+2)]<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Since the denominator cannot be zero,<BR>\n" );
document.write( "x cannot be 0 and x cannot be -2<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Domain: All Real Numbers except x = -2 and x = 0<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );