document.write( "Question 205882: Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
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Algebra.Com's Answer #155487 by checkley77(12844) $\"\"$ $\"About$

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Let x, x+1 & x+2 be the 3 numbers.
\n" ); document.write( "x(x+1)=(x+2)^2-19
\n" ); document.write( "x^2+x=x^2+4x+4-19
\n" ); document.write( "x-4x=4-19
\n" ); document.write( "-3x=-15
\n" ); document.write( "x=-15/-3
\n" ); document.write( "x=5 ans. for the smallest number.
\n" ); document.write( "5+1=6 ans. for the next number
\n" ); document.write( "5+2=7 ans. for the third number.
\n" ); document.write( "Proof:
\n" ); document.write( "5*6=7^2-19
\n" ); document.write( "30=49-19
\n" ); document.write( "30=30\r
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