document.write( "Question 205886: Hi, \r
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document.write( "steve traveled 600 miles at a certain speed. Had he gone 20mph faster, the trip would have taken 1 hour less. Find the speed of his vehicle.\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #155484 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT OR T=D/R \n" ); document.write( "T=600/R \n" ); document.write( "(T-1)=600/(R+20) \n" ); document.write( "T=600/(R+20)+1 \n" ); document.write( "600/R=600/(R+20)+1 \n" ); document.write( "600/R=(600+R+20)/R+20 \n" ); document.write( "600(R+20)=R(R+620) \n" ); document.write( "600R+12000=R^2+620R \n" ); document.write( "R^2+620R-600R-12000=0 \n" ); document.write( "R^2+20R-1,2000=0 \n" ); document.write( "(R-100)(R+120)=0 \n" ); document.write( "R-100=0 \n" ); document.write( "R=100 MPH ANS. FOR THE LONGEST TIME TRIP \n" ); document.write( "R=100+20=120 MPH ANS. FOR THE 1 HOUR SHORTENED TRIP. \n" ); document.write( " \n" ); document.write( " |