document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=205848>Question 205848</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the problem.\r<BR>\n" );
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document.write( "Give the equation of the line that is perpendicular to the line y = -3x + 7 and passes through point (0, -6).<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155445 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155445\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Give the equation of the line that is perpendicular to the line y = -3x + 7 and passes through point (0, -6).<BR>\n" );
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document.write( "The slope of:<BR>\n" );
document.write( "y = -3x + 7<BR>\n" );
document.write( "is -3<BR>\n" );
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document.write( "A line perpendicular, then, must be the negative reciprocal or 1/3.<BR>\n" );
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document.write( "Therefore, our new line:<BR>\n" );
document.write( "m = 1/3<BR>\n" );
document.write( "and crossing:<BR>\n" );
document.write( "(0, -6)<BR>\n" );
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document.write( "Plug that into the \"point slope\" form:<BR>\n" );
document.write( "y - y1 = m(x-x1)<BR>\n" );
document.write( "y - (-6) = (1/3)(x-0)<BR>\n" );
document.write( "y + 6 = (1/3)(x)<BR>\n" );
document.write( "y = (1/3)(x) - 6 (this is what they're looking for)<BR>\n" );
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