document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=28442>Question 28442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is to be no greater than 300 in., and the length must be 125 in.  Write an appropriate inequality, then find the maximum width of the rectangle.\r<BR>\n" );
document.write( "\n" );
document.write( "300>250+2W\r<BR>\n" );
document.write( "\n" );
document.write( "I'm lost am I doing this right. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #15544 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=15544\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It's almost right<BR>\n" );
document.write( "\"no greater than\" is another way of saying \"less than or equal to\"<BR>\n" );
document.write( "the perimeter = 2l + 2w<BR>\n" );
document.write( "2l + 2w <= 300<BR>\n" );
document.write( "w = 125<BR>\n" );
document.write( "2l + 2(125) <= 300<BR>\n" );
document.write( "2l + 250 <= 300 (this is close to what you got)<BR>\n" );
document.write( "subtract 250 from both sides<BR>\n" );
document.write( "2l <= 50<BR>\n" );
document.write( "l <= 25 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );