document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=205762>Question 205762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need your help, please, on a linear equation involving fractions. My problem is 3 over 4 = 1 - 3x-2/x+1. I know I need to find a common denominator, which I think is 4(x+1). Am I right so far? I've done this problem 5 times and came up with 5 different answers. Help.... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155377 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155377\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3 over 4 = 1 - 3x-2/x+1. I know I need to find a common denominator, which I think is 4(x+1). Am I right so far?<BR>\n" );
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document.write( "3/4 = 1 - (3x-2)/(x+1)<BR>\n" );
document.write( "4(x+1) is the common denominator<BR>\n" );
document.write( "Multiply thru by the DEN<BR>\n" );
document.write( "3(x+1) = 4(x+1) - 4(3x-2)<BR>\n" );
document.write( "-(x+1) = -4(3x-2)<BR>\n" );
document.write( "x+1 = 12x-8<BR>\n" );
document.write( "-11x = -9<BR>\n" );
document.write( "x = 9/11 </SPAN>\n" );
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