document.write( "Question 205754: Can you please help me with this problem 3/4=1-3x-2/x+1 \n" ); document.write( "
Algebra.Com's Answer #155374 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Assume the problem is:
\n" ); document.write( "\"3%2F4\" = 1 - \"%28%283x-2%29%29%2F%28%28x%2B1%29%29\"
\n" ); document.write( ":
\n" ); document.write( "multiply the equation by 4(x+1)
\n" ); document.write( "4(x+1)*\"3%2F4\" = 4(x+1)*1 - 4(x+1)*\"%28%283x-2%29%29%2F%28%28x%2B1%29%29\"
\n" ); document.write( ":
\n" ); document.write( "cancel out the denominators and you have:
\n" ); document.write( "3(x+1) = 4(x+1) - 4(3x-2)
\n" ); document.write( ":
\n" ); document.write( "3x + 3 = 4x + 4 - 12x + 8
\n" ); document.write( ":
\n" ); document.write( "combine like terms
\n" ); document.write( "3x + 3 = -8x + 12
\n" ); document.write( ":
\n" ); document.write( "3x + 8x = 12 - 3
\n" ); document.write( ":
\n" ); document.write( "11x = 9
\n" ); document.write( "x = \"9%2F11\"
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\n" ); document.write( ":
\n" ); document.write( "Check the solution in the original equation, you can use the decimal .818 equiv
\n" ); document.write( "to get a close check on it
\n" ); document.write( "\"3%2F4\" = 1 - \"%28%283%28.818%29-2%29%29%2F%28%28.818%2B1%29%29\"
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