document.write( "Question 205492: The length of the Rhombus is 52cm. One of its diagonal is 48 cm. Find the length of the other diagonal and the area of the Rhombus. \n" ); document.write( "

Algebra.Com's Answer #155340 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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The length of the Rhombus is 52cm. One of its diagonal is 48 cm. Find the length of the other diagonal and the area of the Rhombus.
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\n" ); document.write( "you can see that the two diagonals form 4 identical right triangles
\n" ); document.write( "The hypotenuse = 52 cm (one side)
\n" ); document.write( "One leg = half the short diagonal which is 48cm = 24 cm
\n" ); document.write( "The other leg = half the longer diagonal (x)
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\n" ); document.write( "Find the other leg (x)
\n" ); document.write( "x = $\"sqrt%2852%5E2+-+24%5E2%29\"$
\n" ); document.write( "x = 46.13
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\n" ); document.write( "2 * 46.13 = 92.26 cm is the longer diagonal
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\n" ); document.write( "The area will be the total area of the 4 right triangles
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\n" ); document.write( "2 * (46.13 * 24) = 2214.24 sq/cm; (area of the 4 triangles)
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