document.write( "Question 205674: how do I graph 2x-4y=8 using x and y intercepts? \n" ); document.write( "

Algebra.Com's Answer #155299 by Targetweek(62) $\"\"$ $\"About$

You can put this solution on YOUR website!
this should explain it pretty well
\n" ); document.write( "\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "

Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc

Equation $\"2+x+%2B+-4+y+=+8\"$ describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is $\"-a%2Fb+=+-2%2F-4\"$ .

X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. 8/2 = 4.
Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is 8/-4 = -2.
Slope is -2/-4 = 0.5.
Equation in slope-intercept form: y=0.5*x+-2.

$\"graph%28+500%2C+500%2C+4-8%2C+4%2B8%2C+-2-8%2C+-2%2B8%2C+0.5%2Ax%2B-2+%29+\"$ \n" ); document.write( "

\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );