document.write( "Question 205662This question is from textbook Algebra I:An Incremental Development
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\n" ); document.write( "3N^N+3N^Q=9
\n" ); document.write( "2N^N=10-6N^Q
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Algebra.Com's Answer #155287 by RAY100(1637)\"\" \"About 
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(1) 3n^n +3n^q =9,,,,n^n = (9-3n^q)/3 = 3-n^q
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\n" ); document.write( "(2) 2n^n +6n^q =10
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\n" ); document.write( "subst (1) into (2)
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\n" ); document.write( "2(3-n^q) +6n^q =10
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\n" ); document.write( "6-2n^q +6n^q =10
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\n" ); document.write( "4n^q=4
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\n" ); document.write( "n^q=1,,,,,,therefore q=0,,,,anything raised to 0 =1,,,
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\n" ); document.write( "subst into (1),,,,3n^n +3n^0 =9
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\n" ); document.write( "n^n +n^0 =3
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\n" ); document.write( "n^n +1 =3
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\n" ); document.write( "n^n =2
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\n" ); document.write( "n= 1.56
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\n" ); document.write( "check(1) 3*1.56^1.56 +3*1.56^0 =9
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\n" ); document.write( "6 +3=9,,,,,ok
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\n" ); document.write( "(2) 2*1.56^1.56 = 10 - 6*1.56^0
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\n" ); document.write( "4= 10 -6 =4,,,,ok
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