document.write( "Question 205662This question is from textbook Algebra I:An Incremental Development
\n" );
document.write( ": PLEASE help me with this subscripter variable:
\n" );
document.write( "3N^N+3N^Q=9
\n" );
document.write( "2N^N=10-6N^Q \n" );
document.write( "
Algebra.Com's Answer #155287 by RAY100(1637)![]() ![]() ![]() You can put this solution on YOUR website! (1) 3n^n +3n^q =9,,,,n^n = (9-3n^q)/3 = 3-n^q \n" ); document.write( ". \n" ); document.write( "(2) 2n^n +6n^q =10 \n" ); document.write( ". \n" ); document.write( "subst (1) into (2) \n" ); document.write( ". \n" ); document.write( "2(3-n^q) +6n^q =10 \n" ); document.write( ". \n" ); document.write( "6-2n^q +6n^q =10 \n" ); document.write( ". \n" ); document.write( "4n^q=4 \n" ); document.write( ". \n" ); document.write( "n^q=1,,,,,,therefore q=0,,,,anything raised to 0 =1,,, \n" ); document.write( ". \n" ); document.write( "subst into (1),,,,3n^n +3n^0 =9 \n" ); document.write( ". \n" ); document.write( "n^n +n^0 =3 \n" ); document.write( ". \n" ); document.write( "n^n +1 =3 \n" ); document.write( ", \n" ); document.write( "n^n =2 \n" ); document.write( ". \n" ); document.write( "n= 1.56 \n" ); document.write( ". \n" ); document.write( "check(1) 3*1.56^1.56 +3*1.56^0 =9 \n" ); document.write( ". \n" ); document.write( "6 +3=9,,,,,ok \n" ); document.write( ". \n" ); document.write( "(2) 2*1.56^1.56 = 10 - 6*1.56^0 \n" ); document.write( ". \n" ); document.write( "4= 10 -6 =4,,,,ok \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |