document.write( "Question 205634This question is from textbook algebra 1 an integrated approach
\n" ); document.write( ": an elderly wildbeest scents a lion and starts running away at 40mph. .02hours later (about 1 minute ) the lion starts running after the wildbeest at 50mph. presuming the lion and the wildbeest started from the same spot, how long will it take the lion to catch the wildbeest? use the 5 step process, also be sure to draw a distance and fill in a table to set up the problem.
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Algebra.Com's Answer #155265 by Targetweek(62)\"\" \"About 
You can put this solution on YOUR website!
The only 5-step method that i know is the G.U.E.S.S. method which stands for
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\n" ); document.write( "\n" ); document.write( "Sorry i can't help you there but i can help you solve the problem\r
\n" ); document.write( "\n" ); document.write( "1. because 72 seconds is easier to deal with than .02 hours and we can achieve more accurate answers, we can change the mph to ft/s using dimensionsal analysis
\n" ); document.write( "2. Wildebeest speed
\n" ); document.write( "- then simplify and cross out units and you end up with \"%2858.67ft%29%2F%281s%29\"
\n" ); document.write( "3. Lion speed
\n" ); document.write( "- then simplify and cross out units and you end up with \"%2873.33ft%29%2F%281s%29\"
\n" ); document.write( "4. Next we will write 2 equations that represent each animal
\n" ); document.write( "Y will represent the distance traveled and X will represent the time expired
\n" ); document.write( "- Wildebeest -
\n" ); document.write( "Since the Wildebeest started 72s before the lion, it traveled 4224.24ft before the lion started
\n" ); document.write( "\"72%2A58.67+=+4224.24\"
\n" ); document.write( "- the form y=mx+b will be the easiest to use
\n" ); document.write( "- Since the wildebeest has a head start x=0 will be the time that the lion starts
\n" ); document.write( "- so to account for the head start b = 4224.24
\n" ); document.write( "- the slope of the line will be the speed of the animals
\n" ); document.write( "- so the equation for the wildebeest is
\n" ); document.write( "\"y1=58.67x1%2B4224.24\"
\n" ); document.write( "- Lion -
\n" ); document.write( "- because when x=0 the lion hasn't traveled any distance b for the lion = 0
\n" ); document.write( "- so the equation for the lion is
\n" ); document.write( "\"y2=73.33x2+%2B+0\"
\n" ); document.write( "5. Graphing the two equations and finding the intersection will result in a point (x,y) where x is time it took for lion to reach wildebeest and y is how far the lion traveled before reaching the wildebeest
\n" ); document.write( "6. The intersection of the two lines is found at (288.15, 21129.84)
\n" ); document.write( "7. It will take 288.15 seconds for the lion to reach the wildebeest which is...
\n" ); document.write( "\"%28%28288.15s%29%2F1%29%2A%28%281h%29%2F%283600s%29%29\" = .0804 hours or 4.803 min
\n" ); document.write( "8. As far as the table goes...
\n" ); document.write( "x1 [] y1
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\n" ); document.write( "0 [] 4224.24
\n" ); document.write( "50 [] 7157.74
\n" ); document.write( "100 [] 10091.24
\n" ); document.write( "150 [] 13024.74
\n" ); document.write( "200 [] 15958.24
\n" ); document.write( "250 [] 18891.74
\n" ); document.write( "300 [] 21825.24
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\n" ); document.write( "x2 [] y2
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\n" ); document.write( "0 [] 0
\n" ); document.write( "50 [] 366.50
\n" ); document.write( "100 [] 7333.00
\n" ); document.write( "150 [] 10999.50
\n" ); document.write( "200 [] 14666.00
\n" ); document.write( "250 [] 18332.50
\n" ); document.write( "300 [] 21999.00\r
\n" ); document.write( "\n" ); document.write( "sorry if the table doesn't look right and don't forget that the x values are in seconds and the y values are in feet\r
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