document.write( "Question 205566: In 1998, statistics canada reported that 36% of canadian households use the internet. George polled 100 households in his neigbourhood to see if they use the internet more often then the national averga.
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document.write( "A.)Construct a 99% confidence interval for the number of households that use the internet.
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document.write( "B.)George found that 60 households use the internet. Does fall in the 99%confidence interval?? \n" );
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Algebra.Com's Answer #155245 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! In 1998, statistics canada reported that 36% of canadian households use the internet. George polled 100 households in his neigbourhood to see if they use the internet more often then the national averga. \n" ); document.write( "A.)Construct a 99% confidence interval for the number of households that use the internet. \n" ); document.write( "sample proportion: 0.36 \n" ); document.write( "margin of error:::2.326*sqrt(0.36*0.64/sqrt(100) = 0.3531 \n" ); document.write( "99% CI: 0.36 - 0.3531 < p < 0.36 + 0.3531 \n" ); document.write( "99% CI: 0.0069 < p < 0.7131 \n" ); document.write( "-------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "B.)George found that 60 households use the internet. Does fall in the 99%confidence interval?? \n" ); document.write( "60/100 = 0.60 \n" ); document.write( "Ans: Yes \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |