document.write( "Question 205490: How many 3-digit numbers are there for which the sum of the digits of the number is 24?\r
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Algebra.Com's Answer #155243 by Edwin McCravy(20063)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "The smallest one will have the 2nd and 3rd digits as large as\r\n" );
document.write( "possible, which is both 9's, and therefore the hundredths\r\n" );
document.write( "digiuts has to be 6, so 699 is the smallest.\r\n" );
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document.write( " 1.  699\r\n" );
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document.write( "Then the next larger one can be made by\r\n" );
document.write( "increasing the 1st digit by 1 and decreasing the\r\n" );
document.write( "third digit by 1.\r\n" );
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document.write( " 2.  789\r\n" );
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document.write( "The next larger one can be made by increasing the\r\n" );
document.write( "the 2nd digit by 1 and decreasing the 3rd digit\r\n" );
document.write( "by one.\r\n" );
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document.write( " 3.  798\r\n" );
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document.write( "The next larger one can be made increasing the 1st\r\n" );
document.write( "digit by 1, and making the 3rd digit large as possible,\r\n" );
document.write( "and that leaves 7 for the 2nd digit:\r\n" );
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document.write( " 4.  879\r\n" );
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document.write( "The next larger one can be made by increasing the 2nd\r\n" );
document.write( "digit by 1 and decreasing the 3rd by 1:\r\n" );
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document.write( " 5.  888\r\n" );
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document.write( "The next larger one can be made by increasing the 2nd\r\n" );
document.write( "by 1 and decreasing the 3rd digit by 1:\r\n" );
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document.write( " 6.  897\r\n" );
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document.write( "The next larger one will have to have to have a 9 as the\r\n" );
document.write( "1st digit. We make the 3rd digit as large as possible, so\r\n" );
document.write( "it will be 9. That leaves 6 for the 2nd digit:\r\n" );
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document.write( " 7.  969\r\n" );
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document.write( "The next larger one is gotten by increasing the 2nd digit\r\n" );
document.write( "by 1 and decreasing the 3rd digit by 1. \r\n" );
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document.write( " 8.  978\r\n" );
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document.write( "The next larger one is gotten by increasing the 2nd digit\r\n" );
document.write( "by 1 and decreasing the 3rd digit by 1.\r\n" );
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document.write( " 9.  987\r\n" );
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document.write( "The only thing left to do is increase the 2nd digit by 1\r\n" );
document.write( "and decrease the 3rd digit by 1.\r\n" );
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document.write( "10.  996\r\n" );
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document.write( "That's the largest one possible.\r\n" );
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document.write( "So the answer is \"There are 10.\"\r\n" );
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document.write( "Edwin
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