document.write( "Question 205613: √x +2 x =0
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document.write( "I squared both sides to get
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document.write( "(√x+2)^2 – x^2 = 0 then simplifying it I got,
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document.write( "-x^2 + x+2 = 0 setting up the quadratic equation I got
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document.write( "(-x +2)(x+1)=0 setting each side to zero,
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document.write( "-x+2 =0 and x+1=0 solving for x in each equation
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document.write( "-x+2-2=0-2 =
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document.write( "X=-2 and for the other one
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document.write( "X+1-1=0-1=
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document.write( "X=-1 so the solution set is {-2,-1) is this correct???
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Algebra.Com's Answer #155242 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Let \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So y = 0 or y = -1/2 \n" ); document.write( "Now convert back to x \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The only real solution is x = 0\r \n" ); document.write( "\n" ); document.write( "See this for a plot --> http://www82.wolframalpha.com/input/?i=x^(1%2F2)+%2B+2x+%3D+0 \n" ); document.write( " |