document.write( "Question 205482: The ratio of two sums of money is 4:3. If the larger sum of money is increased by 40$, the ratio becomes 2:1. Find the sum of the money. \n" ); document.write( "
Algebra.Com's Answer #155154 by ankor@dixie-net.com(22740)\"\" \"About 
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The ratio of two sums of money is 4:3.
\n" ); document.write( " If the larger sum of money is increased by 40$, the ratio becomes 2:1.
\n" ); document.write( " Find the sum of the money.
\n" ); document.write( ":
\n" ); document.write( "Two sums of money:, x & y
\n" ); document.write( "\"The ratio of two sums of money is 4:3.\"
\n" ); document.write( "\"x%2Fy\" = \"4%2F3\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "3x = 4y
\n" ); document.write( "x = \"4%2F3\"y
\n" ); document.write( ":
\n" ); document.write( "\" If the larger sum of money is increased by 40$, the ratio becomes 2:1.\"
\n" ); document.write( "\"%28%28x%2B40%29%29%2Fy\" = \"2%2F1\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "2y = (x+40)
\n" ); document.write( ":
\n" ); document.write( "Find the sum of the money.
\n" ); document.write( "Replace x with \"4%2F3\"y in the above equation
\n" ); document.write( "2y = \"4%2F3\"y + 40
\n" ); document.write( "multiply equation by 3 to get rid of the denominator
\n" ); document.write( "3(2y) = 3*\"4%2F3\"y + 3(40)
\n" ); document.write( "6y = 4y + 120
\n" ); document.write( "6y - 4y = 120
\n" ); document.write( "2y = 120
\n" ); document.write( "y = $60 is the smaller amt
\n" ); document.write( ":
\n" ); document.write( "find x
\n" ); document.write( "x = \"4%2F3\"(60)
\n" ); document.write( "x = 4(20)
\n" ); document.write( "x = $80 is the larger amt
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