document.write( "Question 205482: The ratio of two sums of money is 4:3. If the larger sum of money is increased by 40$, the ratio becomes 2:1. Find the sum of the money. \n" ); document.write( "
Algebra.Com's Answer #155154 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The ratio of two sums of money is 4:3. \n" ); document.write( " If the larger sum of money is increased by 40$, the ratio becomes 2:1. \n" ); document.write( " Find the sum of the money. \n" ); document.write( ": \n" ); document.write( "Two sums of money:, x & y \n" ); document.write( "\"The ratio of two sums of money is 4:3.\" \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "3x = 4y \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( "\" If the larger sum of money is increased by 40$, the ratio becomes 2:1.\" \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "2y = (x+40) \n" ); document.write( ": \n" ); document.write( "Find the sum of the money. \n" ); document.write( "Replace x with \n" ); document.write( "2y = \n" ); document.write( "multiply equation by 3 to get rid of the denominator \n" ); document.write( "3(2y) = 3* \n" ); document.write( "6y = 4y + 120 \n" ); document.write( "6y - 4y = 120 \n" ); document.write( "2y = 120 \n" ); document.write( "y = $60 is the smaller amt \n" ); document.write( ": \n" ); document.write( "find x \n" ); document.write( "x = \n" ); document.write( "x = 4(20) \n" ); document.write( "x = $80 is the larger amt \n" ); document.write( " |