document.write( "Question 205385: How would you factor:
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document.write( "3x^3+192
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document.write( "2x^3-11x^2+12x+9
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document.write( "9x^2-3x-2
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document.write( "and
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document.write( "2x^5/4+x^3/4-15x^1/4
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document.write( "p.s. the 5/4, 3/4 and 1/4 in the above equation are exponents (2x raised to the 5/4) \n" );
document.write( "
Algebra.Com's Answer #155031 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! 3x^3 + 192 \n" ); document.write( "Factor out 3 \n" ); document.write( "3(x^3 + 64) \n" ); document.write( "The sum of cubes can be factored to: \n" ); document.write( "3(x + 4)(x^2 - 4x + 16) \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "2x^3 - 11x^2 + 12x + 9\r \n" ); document.write( "\n" ); document.write( "Use long division or synthetic division (divide by 3): \n" ); document.write( "(x-3)(2x^2 - 5x - 3)\r \n" ); document.write( "\n" ); document.write( "Factor again \n" ); document.write( "(x-3)(2x + 1)(x - 3) \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "9x^2 - 3x - 2 \n" ); document.write( "(3x - 2)(3x + 1) \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "and \n" ); document.write( "2x^(5/4) + x^(3/4) - 15x^(1/4) \n" ); document.write( ": \n" ); document.write( "Factor out x^(1/4) \n" ); document.write( "x^(1/4)[2x^(4/4) + x^(2/4) - 15] \n" ); document.write( ": \n" ); document.write( "which is \n" ); document.write( "x^(1/4) [2x + x^(1/2) - 15] \n" ); document.write( ": \n" ); document.write( "Factors to \n" ); document.write( "x^(1/4) [2x^(1/2) - 5][x^(1/2) + 3] \n" ); document.write( " |