document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=205329>Question 205329</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Give the equation of the circle with the given center and radius.<BR>\n" );
document.write( "Center at(1,2); radius =1/2\r<BR>\n" );
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document.write( "Would I use the formula, y-y^1=m*(x-x1)? Thank you for your help on this. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #155007 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=155007\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> No, your formula is the \"point-slope\" form of a straight line.<BR>\n" );
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document.write( "The general equation of a circle is:<BR>\n" );
document.write( "(x-h)^2 + (y-k)^2 = r^2<BR>\n" );
document.write( "where<BR>\n" );
document.write( "(h,k) is the center<BR>\n" );
document.write( "r is the radius<BR>\n" );
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document.write( "Center at(1,2); radius =1/2<BR>\n" );
document.write( "(x-1)^2 + (y-2)^2 = 1/4<BR>\n" );
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