document.write( "Question 205233: Please help me factor the following:
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document.write( "3x^3+192
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document.write( "2x^3-11x^2+12x+9
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document.write( "9x^2-3x-2
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document.write( "and
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document.write( "2x^5/4+x^3/4-15x^1/4
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document.write( "p.s. the 5/4, 3/4 and 1/4 in the above equation are exponents (2x raised to the 5/4)
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document.write( "Thank you \n" );
document.write( "
Algebra.Com's Answer #154989 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! factor the following: \n" ); document.write( "3x^3+192 \n" ); document.write( "= 3(x^3+64) \n" ); document.write( "= 3(x^3+4^3) \n" ); document.write( "= 3{x+4)(x^2-4x+16) \n" ); document.write( "--------------------------------- \n" ); document.write( "2x^3-11x^2+12x+9 \n" ); document.write( "= (2x+1)(2x^2-12x+18) \n" ); document.write( "--------------------------------- \n" ); document.write( "9x^2-3x-2 \n" ); document.write( "= 9x^2-6x+3x-2 \n" ); document.write( "= 3x(3x-2)+(3x-2) \n" ); document.write( "= (3x-2)(3x+1 \n" ); document.write( "-------------------------------- \n" ); document.write( "and \n" ); document.write( "2x^5/4+x^3/4-15x^1/4 \n" ); document.write( "x^(1/4)[2x^2 + x^(1/2) - 15) \n" ); document.write( "-------------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=====================================\r \n" ); document.write( "\n" ); document.write( "p.s. the 5/4, 3/4 and 1/4 in the above equation are exponents (2x raised to the 5/4) \n" ); document.write( " \n" ); document.write( " |