document.write( "Question 205310: Can you please help me solve the problem? It's solving radical equations.
\n" ); document.write( "2x + square root (x+1) =8 \r
\n" ); document.write( "\n" ); document.write( "The only thing in the square root is x + 1. I wasn't sure what sign to use on the keyboard for that.
\n" ); document.write( "I know the answer is 3, but I don't understand how to get it. I know you have to square both sides. Thank you.
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Algebra.Com's Answer #154982 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2x + square root (x+1) =8
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\n" ); document.write( "Isolate the square root term:
\n" ); document.write( "sqrt(x+1) = 8-2x
\n" ); document.write( "---
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "x+1 = 64 -32x + 4x^2
\n" ); document.write( "---
\n" ); document.write( "Modify:
\n" ); document.write( "4x^2 -33x +63 = 0
\n" ); document.write( "(x-3)(4x-21) = 0
\n" ); document.write( "x = 3 or x = 21/4
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\n" ); document.write( "Checking those \"answers\":
\n" ); document.write( "Try x = 3 in 2x + sqrt (x+1) =8 and you get: 6 + sqrt(4) = 8
\n" ); document.write( "6 + 2 = 8
\n" ); document.write( "Good answer.
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\n" ); document.write( "Try x = 21/4 in 2x + sqrt(x+1) =8 and you get
\n" ); document.write( "(21/2) + sqrt(25/4) = 8
\n" ); document.write( "(21/2) + 5/2 = 8
\n" ); document.write( "13 = 8
\n" ); document.write( "That is false so x=21/4 is an extraneous answer.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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