document.write( "Question 205267: Given cos(x)= (-1/10) with 90 degrees\n" ); document.write( "\n" ); document.write( "I solved this...\r
\n" ); document.write( "\n" ); document.write( "cos^2(theta/2)= (1/2)(1+cos(theta))\r
\n" ); document.write( "\n" ); document.write( " =((1/2) ((10/10)-(1/10))
\n" ); document.write( " =(1/2)(9/10)
\n" ); document.write( " =9/20
\n" ); document.write( "cos (theta/2)=sqroot (9/20)
\n" ); document.write( " = 3/ (sqroot20)
\n" ); document.write( " =(3(sqroot20))/20
\n" ); document.write( " =(3*2sqroot5)/20
\n" ); document.write( " =(3sqroot5)/10
\n" ); document.write( "I marked it as NEGATIVE because it is in the second quadrant but it is marked wrong. However, when I submit positive (3sqroot5)/10 it marks it right. Why does it remain positive even though it is in the second quadrant?
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Algebra.Com's Answer #154940 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Given cos(x)= (-1/10) with 90 degrees I solved this...
\n" ); document.write( "cos^2(theta/2)= (1/2)(1+cos(theta))
\n" ); document.write( "=((1/2) ((10/10)-(1/10))
\n" ); document.write( "=(1/2)(9/10)
\n" ); document.write( "=9/20
\n" ); document.write( "cos (theta/2)=sqroot (9/20)
\n" ); document.write( "= 3/ (sqroot20)
\n" ); document.write( "=(3(sqroot20))/20
\n" ); document.write( "=(3*2sqroot5)/20
\n" ); document.write( "=(3sqroot5)/10
\n" ); document.write( "I marked it as NEGATIVE because it is in the second quadrant but it is marked wrong. However, when I submit positive (3sqroot5)/10 it marks it right. Why does it remain positive even though it is in the second quadrant? \r
\n" ); document.write( "\n" ); document.write( "-------
\n" ); document.write( "It accepts the positive answer because you are calculating the
\n" ); document.write( "cos of (theta/2). Although theta is in the 2nd quadrant, theta/2
\n" ); document.write( "is in the 1st quadrant.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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