document.write( "Question 205267: Given cos(x)= (-1/10) with 90 degrees
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document.write( "cos^2(theta/2)= (1/2)(1+cos(theta))\r
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document.write( " =((1/2) ((10/10)-(1/10))
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document.write( " =(1/2)(9/10)
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document.write( " =9/20
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document.write( "cos (theta/2)=sqroot (9/20)
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document.write( " = 3/ (sqroot20)
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document.write( " =(3(sqroot20))/20
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document.write( " =(3*2sqroot5)/20
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document.write( " =(3sqroot5)/10
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document.write( "I marked it as NEGATIVE because it is in the second quadrant but it is marked wrong. However, when I submit positive (3sqroot5)/10 it marks it right. Why does it remain positive even though it is in the second quadrant?
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Algebra.Com's Answer #154940 by stanbon(75887) ![]() You can put this solution on YOUR website! Given cos(x)= (-1/10) with 90 degrees I solved this... \n" ); document.write( "cos^2(theta/2)= (1/2)(1+cos(theta)) \n" ); document.write( "=((1/2) ((10/10)-(1/10)) \n" ); document.write( "=(1/2)(9/10) \n" ); document.write( "=9/20 \n" ); document.write( "cos (theta/2)=sqroot (9/20) \n" ); document.write( "= 3/ (sqroot20) \n" ); document.write( "=(3(sqroot20))/20 \n" ); document.write( "=(3*2sqroot5)/20 \n" ); document.write( "=(3sqroot5)/10 \n" ); document.write( "I marked it as NEGATIVE because it is in the second quadrant but it is marked wrong. However, when I submit positive (3sqroot5)/10 it marks it right. Why does it remain positive even though it is in the second quadrant? \r \n" ); document.write( "\n" ); document.write( "------- \n" ); document.write( "It accepts the positive answer because you are calculating the \n" ); document.write( "cos of (theta/2). Although theta is in the 2nd quadrant, theta/2 \n" ); document.write( "is in the 1st quadrant. \n" ); document.write( "================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |