document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=205250>Question 205250</A>: <I><SPAN STYLE=\"word-break: break-all;\"> TJ plans to erect 132 feet of fencing around his rectangular garden, using his house as one side of the garden.  Each width (x) is 3 feet longer than twice the length (y).  Find the dimensions of the garden. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154937 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154937\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x=2y+3<BR>\n" );
document.write( "2x+(2y+3)=132<BR>\n" );
document.write( "2(2y+3)+2y+3=132<BR>\n" );
document.write( "4y+6+2y+3=132<BR>\n" );
document.write( "6y+9=132<BR>\n" );
document.write( "6y=132-9<BR>\n" );
document.write( "6y=123<BR>\n" );
document.write( "y=123/6<BR>\n" );
document.write( "y=20.5 ans. for the length.<BR>\n" );
document.write( "x=2*20.5+3<BR>\n" );
document.write( "x=41+3<BR>\n" );
document.write( "x=44 ans for the width.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "2*44+(2*20.5+3)=132<BR>\n" );
document.write( "88+41+3=132<BR>\n" );
document.write( "132=132 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );