document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=205106>Question 205106</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the LCD of:\r<BR>\n" );
document.write( "\n" );
document.write( "7/a^2+2a-63 , 8/a+9\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154930 by </B><A HREF=/tutors/aboutme.mpl?userid=profemmanuel2q@yahoo.com><B>profemmanuel2q@yahoo.com(15)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=profemmanuel2q@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154930\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the LCD of:<BR>\n" );
document.write( "7/a^2+2a-63 , 8/a+9 <BR>\n" );
document.write( "Before you can solve this you need to factorise,a^2+2a-63<BR>\n" );
document.write( "when you factorise a^2+2a-63, you will get (a - 7)(a + 9)<BR>\n" );
document.write( "So therefore taking both denominators thats (a + 9) and a^2+2a-63, the LCM is <BR>\n" );
document.write( "(a - 7)(a + 9) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );