document.write( "Question 205244This question is from textbook Mathematics in our world
\n" ); document.write( ": Dorothy is 6 years older than Ricardo. The product of their present ages is twice what the product of their ages was 6 years ago. How old is Dorothy? \n" ); document.write( "

Algebra.Com's Answer #154924 by ptaylor(2198) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Let x=Dorothy's age; x-6=Dorothy's age 6 years ago
\n" ); document.write( "Then x-6=Ricardo's age; x-12=Ricardo's age 6 years ago\r
\n" ); document.write( "\n" ); document.write( "Now we are told that:
\n" ); document.write( "x(x-6)=2(x-6)(x-12) divide each side by x-6 (assuming that x is not equal to zero)
\n" ); document.write( "x=2(x-12) or
\n" ); document.write( "x=2x-24 subtract 2x from each side
\n" ); document.write( "x-2x=2x-2x-24
\n" ); document.write( "-x=-24
\n" ); document.write( "x=24--------------------------Dorothy's current age
\n" ); document.write( "x-6=24-6=18-------------------Ricardo's current age\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "24*18=2*18*12 or
\n" ); document.write( "24=2*12
\n" ); document.write( "24=24\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( "

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