document.write( "Question 205194: Please help with me find an equation of line l and solve for y when Line l goes through (0,0) and is perpendicular to the line through (0,6) and (-5,0). I am stumped because I don't think there is a slope for the first line. Any help is greatly appreciated. \n" ); document.write( "

Algebra.Com's Answer #154918 by checkley77(12844) $\"\"$ $\"About$

You can put this solution on YOUR website!
(0,6)(-5,0)
\n" ); document.write( "The equation for this line is:
\n" ); document.write( "Y=mX+b
\n" ); document.write( "m=slope=(y2-y1)/(x2-x1)=(0-6)/(-5-0)=-6/-5=6/5 ans.
\n" ); document.write( "6=6/5*0+b
\n" ); document.write( "6=b ans. for the y intercept.
\n" ); document.write( "y=6x/5+6 is the equation for this line. (red line)
\n" ); document.write( "A perpendicular line will have a slope=-5/6 passing through (0,0).
\n" ); document.write( "0=-5/6*0+b
\n" ); document.write( "0=b ans. for the y intercept for this line.
\n" ); document.write( "y=-5x/6+0s the equation for thjis line. (green line)
\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-6%2C+6%2C+-6%2C+6%2C+6x%2F5+%2B6%2C+y+=+-5x%2F6+%29+\"$ (graph 300x300 pixels, x from -6 to 6, y from -6 to 6, of TWO functions 6x/5 +6 and y = -5x/6).
\n" ); document.write( " \n" ); document.write( "

\n" );