document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=205220>Question 205220</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the sum of each series<BR>\n" );
document.write( "-60 + (-59) + (-58) + . . . . + 87 + 88 + 89 + 90 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154905 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154905\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the sum of each series<BR>\n" );
document.write( "-60 + (-59) + (-58) + . . . . + 87 + 88 + 89 + 90<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Formula: S(n) = (n/2)(1st + last)<BR>\n" );
document.write( "n = 90+1+60 = 151 terms\r<BR>\n" );
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document.write( "-------<BR>\n" );
document.write( "S(151) = (151/2)(-60+90)<BR>\n" );
document.write( "= 75.5*30<BR>\n" );
document.write( "= 2265<BR>\n" );
document.write( "================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );