document.write( "Question 205193: Given a zero x=2, of the polynomial: x^3-4x^2+21x-34=0, find the others.
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document.write( "Did I do this right?\r
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document.write( "x(x^2-4x+21)-34=0
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document.write( "x(x-7)(x+3)-34=0
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document.write( "x= -7 x= -3\r
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document.write( "If I am off base, can you show the correct way to do this problem? Thank you \n" );
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Algebra.Com's Answer #154896 by edjones(8007)![]() ![]() You can put this solution on YOUR website! x-2=0 since 2 is a zero. \n" ); document.write( "(x^3-4x^2+21x-34)/(x-2) Long division \n" ); document.write( "=x^2-2x+17 \n" ); document.write( "x^2-2x+17=0 \n" ); document.write( "x=1+4i, x=1-4i The other 2 zeros. Quadratic formula (see below) \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( ". \n" ); document.write( "
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