document.write( "Question 205196: Measure the distance of the diagonal (corner to corner) of the screen on your computer monitor to the nearest tenth of a centimeter or six tenths of a inch. Measure the height of the screen the vertical as well. Use the pythagorean theorem to find the horizontal. 13in diagonal and 8 in. high? I cannot get this. Ty in advance judy \n" ); document.write( "
Algebra.Com's Answer #154894 by nerdybill(7384)\"\" \"About 
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Measure the distance of the diagonal (corner to corner) of the screen on your computer monitor to the nearest tenth of a centimeter or six tenths of a inch. Measure the height of the screen the vertical as well. Use the pythagorean theorem to find the horizontal. 13in diagonal and 8 in. high?
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\n" ); document.write( "The \"vertical\" and the \"horizontal\" measurements represents the sides while the \"diagonal\" is the hypotenuse.
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\n" ); document.write( "Let h=horizontal
\n" ); document.write( "then
\n" ); document.write( "h^2 + 8^2 = 13^2
\n" ); document.write( "h^2 + 64 = 169
\n" ); document.write( "h^2 = 105
\n" ); document.write( "h = 10.25 inches (horizontal length)
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