document.write( "Question 205138: Please help me simplify the following:\r
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\n" ); document.write( "\n" ); document.write( "p.s. the -3/2 and -1/2 in the equation above are exponents. meaning: x(1-2x) raised to the negative 3/2 \n" ); document.write( "
Algebra.Com's Answer #154851 by Edwin McCravy(20065)\"\" \"About 
You can put this solution on YOUR website!
Please help me simplify the following:\r
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document.write( "Use the principle \"A%2ALN%28B%29=LN%28B%5EA%29\" to rewrite\r\n" );
document.write( "the first and last terms:\r\n" );
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document.write( "\"LN%28x-3%29%5E2%2BLN%28x%2B2%29-LN%28x%5E6%29\"\r\n" );
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document.write( "Use the principle: \"LN%28A%29%2BLN%28B%29=LN%28A%2AB%29\" to rewrite\r\n" );
document.write( "the first two terms:\r\n" );
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document.write( "\"LN%28%28x-3%29%5E2%28x%2B2%29%29-LN%28x%5E6%29\"\r\n" );
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document.write( "Use the principle: \"LN%28A%29-LN%28B%29=LN%28A%2FB%29\" to rewrite\r\n" );
document.write( "the expression:\r\n" );
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document.write( "\"LN%28%28%28x-3%29%5E2%28x%2B2%29%29%2F%28x%5E6%29%29\"\r\n" );
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document.write( "The smaller of those two exponents is \"-3%2F2\",\r\n" );
document.write( "so we factor out \"%281-2x%29%5E%28-3%2F2%29\"\r\n" );
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document.write( "You may wonder where I got that \"1\" exponent.\r\n" );
document.write( "When you factor one power of \"%281-2x%29\" out of\r\n" );
document.write( "another power of \"%281-2x%29\", you divide by \r\n" );
document.write( "subtracting exponents, and \"%28-1%2F2%29-%28-3%2F2%29=-1%2F2%2B3%2F2=2%2F2=1\"\r\n" );
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document.write( "So we can now erase that 1 exponent:\r\n" );
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document.write( "Removing the parentheses within parentheses:\r\n" );
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document.write( "Edwin
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