document.write( "Question 28491: X^2/4-X/1=5/4 \n" ); document.write( "

Algebra.Com's Answer #15485 by sdmmadam@yahoo.com(530) $\"\"$ $\"About$

You can put this solution on YOUR website!
X^2/4-X/1=5/4 ----(*)
\n" ); document.write( "Multiplying by 4 through out
\n" ); document.write( "x^2-4x=5 ----(2)
\n" ); document.write( "(observe that the first term is square of x,the mid term is negative and (-4x) is therefore the product -2X(2)X(x) which is of the form -2ab.We have on the LHS an expression of the form (a^2-2ab) and so we need the quantity b^2 = 2^2 to complete the square)
\n" ); document.write( "Adding 2^2 on both the sides,
\n" ); document.write( "[(x)^2-2X(2)X(x) +(2)^2] = 5 +(2)^2
\n" ); document.write( "[(x-2)^2]=9
\n" ); document.write( "(x-2)= (+ or minus)3
\n" ); document.write( "x= +2 (+ or minus)3
\n" ); document.write( "That is x= 2+3 or x = 2-3
\n" ); document.write( "x=5 and x = -1
\n" ); document.write( "Answer: x=5 and x = -1
\n" ); document.write( "Verification: x = 5 in (*) implies
\n" ); document.write( "LHS = 25/4-5 = 5/4 =RHS
\n" ); document.write( "x= -1 in (*)
\n" ); document.write( "LHS = 1/4+1 = 5/4 = RHS
\n" ); document.write( "Note: Always verify things by substituting the values in the given raw form of data instead of in your simlified later forms.
\n" ); document.write( " \n" ); document.write( "

\n" );