document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=205095>Question 205095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi.  I am having trouble with this problem:\r<BR>\n" );
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document.write( "Expressed in a + bi form, 5/ 3 + i is equuivalent to...\r<BR>\n" );
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document.write( "A) 15 - 5i,  B) (3/2) - (1/2i),  C) (5/3) - 5i,  D)  (15/8) - (5/8i)   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154813 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154813\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Answer is B<BR>\n" );
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document.write( "Multiply by (3-i)/(3-i):<BR>\n" );
document.write( "5/(3+i) * (3-i)/(3-i)<BR>\n" );
document.write( "= 5(3-i)/(3+i)(3-i)<BR>\n" );
document.write( "= 5(3-i)/(9-3i+3i+1)<BR>\n" );
document.write( "= 5(3-i)/(9+1)<BR>\n" );
document.write( "= 5(3-i)/10<BR>\n" );
document.write( "= (15-5i)/10<BR>\n" );
document.write( "= 15/10 - 5i/10<BR>\n" );
document.write( "= (3/2) - (1/2)i  </SPAN>\n" );
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