document.write( "Question 3471: Sorry that didn't come out right\r
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document.write( "I= nE/nr+R for n \n" );
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Algebra.Com's Answer #1548 by Pieter(35)![]() ![]() ![]() You can put this solution on YOUR website! 1) x²-4=0 \n" ); document.write( "you bring the 4 to the other side: x²=4 thus x is 2 OR -2 because (-2)² gives also 4. \n" ); document.write( "2) x²+x=0 \n" ); document.write( "You have heard about (this are the solutions of a second degree equation in the form of: ax²+bx+c=0) i guess. in this formula, a=1;b=1;c=0 so this gives: and if you count a bit, you get that 0 and -1 are the roots. \n" ); document.write( "3)x^2+7x+12=0 \n" ); document.write( "Again the formula, and filled in, it gives: . The solutions are: -3 and -4 \n" ); document.write( "4)x^2+5x=-4 \n" ); document.write( "Also here we can use the formula but we first have to put the -4 on the left side: x²+5x+4=0 (the polynome hase to be zero!) and then again you have to apply the formula. You can do it by now i guess? I find -1 and -4. \n" ); document.write( "5)3x^2+5x-10=0 \n" ); document.write( "THe same over and over again: a=3 b=5, c=-10. \n" ); document.write( "6)4x^2+3x+8=0 \n" ); document.write( "Again the same. This equation won't have any solutions because b²-4ac is smaller than 0 and in the plane of the real numbers that isn't possible. (in the complex plane it is!) \n" ); document.write( "Greets, contact me if you have any questions!\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |