document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=205054>Question 205054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone help me with the following problem:  Solve the following systems of equatons algebraically.  Be certain you have solved both variables in teh frist sytem of equations and all 3 variables in teh second system. 1,  5x+y = 5<BR>\n" );
document.write( "                    3x-5y = -63\r<BR>\n" );
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document.write( "2.       a+b+3c= - 8<BR>\n" );
document.write( "           2b-c=15<BR>\n" );
document.write( "           3a+2c=7.\r<BR>\n" );
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document.write( "This is the answer I got am I on the right track?  1. x= 4 and y = -1       2. a=77, b -8  and c= - 30.  If I am wrong can you show me how you solved it?  Thank you!!!!   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154781 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154781\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Can someone help me with the following problem: Solve the following systems of equatons algebraically. Be certain you have solved both variables in teh frist sytem of equations and all 3 variables in teh second system. <BR>\n" );
document.write( "1, <BR>\n" );
document.write( "5x+y = 5<BR>\n" );
document.write( "3x-5y = -63<BR>\n" );
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document.write( "Your solution is incorrect.<BR>\n" );
document.write( "5x+y = 5<BR>\n" );
document.write( "3x-5y = -63<BR>\n" );
document.write( "--<BR>\n" );
document.write( "Solving 1st equation for \"y\" you get y = -5x+5<BR>\n" );
document.write( "Substituting that into the 2nd equation you can solve for \"x\":<BR>\n" );
document.write( "3x -5(-5x+5) = -63<BR>\n" );
document.write( "3x +25x-25 = -63<BR>\n" );
document.write( "28x = 38<BR>\n" );
document.write( "x = 19/14<BR>\n" );
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document.write( "Substitute that into y = -5x+5 = -5(19/14)+5 = -95/14 + 70/14 = -25/14<BR>\n" );
document.write( "Solution: x = (19/14) ; y = (-25/14)\r<BR>\n" );
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document.write( "------------------------\r<BR>\n" );
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document.write( "2. <BR>\n" );
document.write( "a + b+3c =-8<BR>\n" );
document.write( "0a+2b-c  =15<BR>\n" );
document.write( "3a+0b+2c =7<BR>\n" );
document.write( "------------------------<BR>\n" );
document.write( "From the 2nd equation b = (1/2)c + (15/2)<BR>\n" );
document.write( "From the 3rd equation a = (-2/3)c + (7/3)<BR>\n" );
document.write( "--------------------------------------------<BR>\n" );
document.write( "Substitute those into the 1st equation and solve for \"c\":<BR>\n" );
document.write( "(-2/3)c + (7/3) + (1/2)c + (15/2) + 3c = -8<BR>\n" );
document.write( "Multiply thru by 6 to get:<BR>\n" );
document.write( "-4c + 14 + 3c + 45 +18c = -48<BR>\n" );
document.write( "17c = -107<BR>\n" );
document.write( "c = -107/17<BR>\n" );
document.write( "-------------------<BR>\n" );
document.write( "Substitute that into b=(1/2)c+(15/2) to get b = 74/17<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Substitute the value for c into a=(-2/3)c + (7/3) to get a = 111/17<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " <BR>\n" );
document.write( "This is the answer I got am I on the right track? <BR>\n" );
document.write( "1. x= 4 and y = -1 <BR>\n" );
document.write( "2. a=77, b -8 and c= - 30. <BR>\n" );
document.write( "If I am wrong can you show me how you solved it? </SPAN>\n" );
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