document.write( "Question 28478: Rationalize the denominator:\r
\n" ); document.write( "\n" ); document.write( " 2____
\n" ); document.write( " √[6] - √[5]\r
\n" ); document.write( "\n" ); document.write( "This one really lost me, can you show the steps???
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Algebra.Com's Answer #15478 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Rationalise the denominator:
\n" ); document.write( "\"2%2F%28%28sqrt%286%29-sqrt%285%29%29%29\" Multiply both the numerator and the denominator by the conjugate of\"%28sqrt%286%29-sqrt%285%29%29\" which is\"%28sqrt%286%29%2Bsqrt%285%29%29\"
\n" ); document.write( " Simplify.
\n" ); document.write( "\"2%28sqrt%286%29%2Bsqrt%285%29%29%2F%286-5%29\"=\"2%28sqrt%286%29%2Bsqrt%285%29%29\" or \"2sqrt%286%29%2B2sqrt%285%29\"\r
\n" ); document.write( "\n" ); document.write( "Explanation:\"%28a-b%29%28a%2Bb%29+=+a%5E2-b%5E2\" In your problem,\"a+=+sqrt%286%29\" and \"b+=+sqrt%285%29\" so \"a%5E2+=+%28sqrt%286%29%29%5E2\" = 6. And \"b%5E2+=+%28sqrt%285%29%29%5E2\" = 5
\n" ); document.write( "Multiply \"sqrt%286%29-sqrt%285%29\" by its conjugate \"sqrt%286%29%2Bsqrt%285%29\" using the FOIL method, it works out like this.\r
\n" ); document.write( "\n" ); document.write( " but, as you can see (I hope), the centre terms drop out leaving you with (6 - 5 = 1)
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