document.write( "Question 28480: Quadratic Equations\r
\n" ); document.write( "\n" ); document.write( " Solve by factoring:\r
\n" ); document.write( "\n" ); document.write( "x2 – 9x = -20\r
\n" ); document.write( "\n" ); document.write( "So lost \n" ); document.write( "
Algebra.Com's Answer #15477 by Earlsdon(6294)\"\" \"About 
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Solve by factoring:
\n" ); document.write( "\"x%5E2-9x+=+-20\" First, add 20 to both sides of the equation.
\n" ); document.write( "\"x%5E2-9x%2B20+=+0\" Now factor the left side.\r
\n" ); document.write( "\n" ); document.write( "Factoring: The two factors will have the form\"%28x%2Ba%29%28x%2Bb%29\" where: a+b = -9
\n" ); document.write( "and a X b = 20\r
\n" ); document.write( "\n" ); document.write( "Try these: a = -4 and b = -5
\n" ); document.write( "a+b = (-4)+(-5) = -9
\n" ); document.write( "a X b = (-4)(-5) = 20 So these will work.
\n" ); document.write( "The factors are:
\n" ); document.write( "(x-4)(x-5), so we have:
\n" ); document.write( "(x-4)(x-5) = 0 Apply the zero products principle.
\n" ); document.write( "x-4 = 0 and/or x-5 = 0
\n" ); document.write( "If x-4 = 0, then x = 4
\n" ); document.write( "If x-5 = 0, then x = 5\r
\n" ); document.write( "\n" ); document.write( "The roots are:
\n" ); document.write( "x = 4
\n" ); document.write( "x = 5
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