document.write( "Question 204888: 4. A 200 lb batch of feed is being formulated using corn and soybean meal. The corn is 6.5% crude protein and the soybean meal is 45% crude protein. The final diet should be 15% crude protein. How much of each ingredient should be added to mix this batch of feed?\r
\n" ); document.write( "\n" ); document.write( "(HINT: Take x to be the lbs of corn and y to be the lbs of soybean meal. Develop two equations and solve them.)
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Algebra.Com's Answer #154763 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "OK, WE'LL FOLLOW THE HINT:\r
\n" ); document.write( "\n" ); document.write( "Let x=lbs of corn
\n" ); document.write( "And y=lbs of soybean meal
\n" ); document.write( "Now we are told that:
\n" ); document.write( "x+y=200-------------------------eq1
\n" ); document.write( "Now we know that the amount of pure crude protein before they are mixed (0.065x+0.45y) has to equal the amount of pure crude protein after they are mixed (0.15*200), so:\r
\n" ); document.write( "\n" ); document.write( "0.065x+0.45y=0.15*200 simplify
\n" ); document.write( "0.065x+0.45y=30------------------------eq2\r
\n" ); document.write( "\n" ); document.write( "Multiply eq1 by 0.065 (we get: 0.065x+0.065y=13) and then subtract it from eq2 and we get:
\n" ); document.write( "0.385y=17 divide each side by 0.385
\n" ); document.write( "y=44.2 lb ----------------------lbs of soybean meal needed
\n" ); document.write( "substitute y=44.2 into eq1:
\n" ); document.write( "x+44.2=200
\n" ); document.write( "x=200-44.2=155.8---------------lbs of corn needed\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "0.065*155.8+0.45*44.2=0.15*200
\n" ); document.write( "10.1+19.9=30
\n" ); document.write( "30=30\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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