document.write( "Question 205006: Can you please help me thanks alot
\n" ); document.write( "Reduce (csc^ x - sec^ x) to an expression containing only tan x.
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Algebra.Com's Answer #154745 by Edwin McCravy(20066)\"\" \"About 
You can put this solution on YOUR website!
Can you please help me thanks alot
\n" ); document.write( "Reduce \"%28csc%5E2x+-+sec%5E2x%29\" to an expression containing only \"tan%28x%29\".
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document.write( "The two identities we have involving cosecant and secant are\r\n" );
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document.write( "\"1+%2B+Tan%5E2phi=sec%5E2phi\" and \"1+%2B+Cot%5E2phi=csc%5E2phi\"\r\n" );
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document.write( "Using them we have\r\n" );
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document.write( "\"%28csc%5E2x+-+sec%5E2x%29\"\r\n" );
document.write( "\"1%2BCot%5E2x+-+%281%2BTan%5E2x%29\"\r\n" );
document.write( "\"1%2BCot%5E2x+-+1-Tan%5E2x\"\r\n" );
document.write( "\"Cot%5E2x-Tan%5E2x\"\r\n" );
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document.write( "Now we can get use the identity \"Cot%28phi%29=1%2FTan%28phi%29\" \r\n" );
document.write( "to get the term in cotangent in terms of tangent:\r\n" );
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document.write( "\"1%2F%28Tan%5E2x%29-Tan%5E2x\"\r\n" );
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document.write( "That's actually good enough there, but maybe your teacher\r\n" );
document.write( "wants you to combine those terms:\r\n" );
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document.write( "\"1%2F%28Tan%5E2x%29-Tan%5E2x\"\r\n" );
document.write( "\"1%2F%28Tan%5E2x%29-%28Tan%5E2x%29%2F1\"\r\n" );
document.write( "\"1%2F%28Tan%5E2x%29-%28Tan%5E2x%29%28Tan%5E2x%29%2F%281%28Tan%5E2x%29%29\"\r\n" );
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document.write( "\"1%2F%28Tan%5E2x%29-%28Tan%5E4x%29%2F%28Tan%5E2x%29\"\r\n" );
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document.write( "\"%281-Tan%5E4x%29%2F%28Tan%5E2x%29\"\r\n" );
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document.write( "Edwin
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