document.write( "Question 204990: solve for x: log(x + 2) + log(x-1)=1 \n" ); document.write( "
Algebra.Com's Answer #154726 by stanbon(75887)\"\" \"About 
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solve for x: log(x + 2) + log(x-1)=1
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\n" ); document.write( "log[(x+2)(x-1)] = 1
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\n" ); document.write( "(x+2)(x-1) = 10^1
\n" ); document.write( "x^2 + x - 2 = 10
\n" ); document.write( "x^2 + x -12 = 0
\n" ); document.write( "(x+4)(x-3) = 0
\n" ); document.write( "x = -4 or x = 3
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\n" ); document.write( "Only x=3 is a true solution as log(x+2) and log(x-1) would
\n" ); document.write( "be meaningless if x = -4.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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