document.write( "Question 204987: If the numerator of a certain fraction is increased by 5 and the denominator is decreased by 1, the resulting fraction is 8/3. However, if the numerator of the original fraction is doubled and the denominator is increased by 7, the resulting fraction is 6/11. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #154723 by stanbon(75887) ![]() You can put this solution on YOUR website! If the numerator of a certain fraction is increased by 5 and the denominator is decreased by 1, the resulting fraction is 8/3. However, if the numerator of the original fraction is doubled and the denominator is increased by 7, the resulting fraction is 6/11. Find the original fraction \n" ); document.write( "---------------------------------------------------------------- \n" ); document.write( "Let the original fraction be x/y. \n" ); document.write( "Equations: \n" ); document.write( "(x+5)/(y-1) = 8/3 \n" ); document.write( "--- \n" ); document.write( "(2x)/(y+7)/ 6/11 \n" ); document.write( "------------------------------------ \n" ); document.write( "Rearrange: \n" ); document.write( "3(x+5) = 8(y-1) \n" ); document.write( "11(2x) = 6(y+7) \n" ); document.write( "------------------- \n" ); document.write( "Modify: \n" ); document.write( "8y - 3x = 23 \n" ); document.write( "6y -22x = -42 \n" ); document.write( "------------------------ \n" ); document.write( "Set up for elimination: \n" ); document.write( "48y - 18x = 6*23 \n" ); document.write( "48y -176x = 8*-42 \n" ); document.write( "--- \n" ); document.write( "Subtract the 2nd equation from the 1st to solve for \"x\": \n" ); document.write( "158x = 474 \n" ); document.write( "x = 3 \n" ); document.write( "--- \n" ); document.write( "Substitute into 8y -3x = 23 to solve for \"y\": \n" ); document.write( "8y -3*3 = 23 \n" ); document.write( "8y - 9 = 23 \n" ); document.write( "8y = 32 \n" ); document.write( "y = 4 \n" ); document.write( "---------------- \n" ); document.write( "Original fraction: x/y = 3/4 \n" ); document.write( "===================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |