document.write( "Question 204987: If the numerator of a certain fraction is increased by 5 and the denominator is decreased by 1, the resulting fraction is 8/3. However, if the numerator of the original fraction is doubled and the denominator is increased by 7, the resulting fraction is 6/11. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #154723 by stanbon(75887)\"\" \"About 
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If the numerator of a certain fraction is increased by 5 and the denominator is decreased by 1, the resulting fraction is 8/3. However, if the numerator of the original fraction is doubled and the denominator is increased by 7, the resulting fraction is 6/11. Find the original fraction
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\n" ); document.write( "Let the original fraction be x/y.
\n" ); document.write( "Equations:
\n" ); document.write( "(x+5)/(y-1) = 8/3
\n" ); document.write( "---
\n" ); document.write( "(2x)/(y+7)/ 6/11
\n" ); document.write( "------------------------------------
\n" ); document.write( "Rearrange:
\n" ); document.write( "3(x+5) = 8(y-1)
\n" ); document.write( "11(2x) = 6(y+7)
\n" ); document.write( "-------------------
\n" ); document.write( "Modify:
\n" ); document.write( "8y - 3x = 23
\n" ); document.write( "6y -22x = -42
\n" ); document.write( "------------------------
\n" ); document.write( "Set up for elimination:
\n" ); document.write( "48y - 18x = 6*23
\n" ); document.write( "48y -176x = 8*-42
\n" ); document.write( "---
\n" ); document.write( "Subtract the 2nd equation from the 1st to solve for \"x\":
\n" ); document.write( "158x = 474
\n" ); document.write( "x = 3
\n" ); document.write( "---
\n" ); document.write( "Substitute into 8y -3x = 23 to solve for \"y\":
\n" ); document.write( "8y -3*3 = 23
\n" ); document.write( "8y - 9 = 23
\n" ); document.write( "8y = 32
\n" ); document.write( "y = 4
\n" ); document.write( "----------------
\n" ); document.write( "Original fraction: x/y = 3/4
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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