document.write( "Question 204955: I am having trouble with this:
\n" ); document.write( "500 tickets for prizes are sold for $2 each. Five prizes will be awarded - one for $300, one for $200, and three for $50. Steven purchases one fo the tickets.\r
\n" ); document.write( "\n" ); document.write( "a)Find the expected value.
\n" ); document.write( "b)Find the fair price of the ticket.\r
\n" ); document.write( "\n" ); document.write( "So far, for a, I think you would do something like this: \r
\n" ); document.write( "\n" ); document.write( "1st prize: 1/500 = 0.002
\n" ); document.write( "2nd prize: 1/500 = 0.002
\n" ); document.write( "3rd prize: 3/500 = 0.006\r
\n" ); document.write( "\n" ); document.write( "so, $300(0.002) + $200(0.002) + $50(0.006) = $1.30\r
\n" ); document.write( "\n" ); document.write( "For b, I do not know where to begin.
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Algebra.Com's Answer #154717 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
a) Good job so far, but you're forgetting to subtract the price to play the game. You need to subtract $2 from $1.30 to get: 1.3-2=-0.7\r
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\n" ); document.write( "\n" ); document.write( "So you lose $0.70 (70 cents) on average each time you play. \r
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\n" ); document.write( "\n" ); document.write( "b) In order for it to be a fair game, the price to play must be equal to the amount of money you lose. This way, their difference will be zero. Note: a 'fair game' is where you neither win money or lose money (ie you break even). So the fair price is $1.30 since (expected gain - price to play = 1.30 - 1.30 = 0)
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