document.write( "Question 204889: 5. 5. A 200 lb batch of feed is being formulated using corn, dried distiller’s grain (DDGs) and soybean meal. The corn is 6.5% crude protein and the soybean meal is 45% crude protein. Dried distiller’s grain is 27% crude protein. The final diet should be 15% crude protein. The final diet will include 20 lbs of DDGs. How much corn and soybean meal should be added to mix this batch of feed?\r
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document.write( "(HINT: Take x to be lbs of corn, y to be lbs of soybean meal, z to be lbs of DDGs. You already know what one of these should be.)
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Algebra.Com's Answer #154688 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! OK, We'll use your hint (sort of)\r \n" ); document.write( "\n" ); document.write( "Let x=lbs of corn needed \n" ); document.write( "We are told that 20 lb=lbs of DDGs needed \n" ); document.write( "Then 200-(x+20)=200-x-20= \n" ); document.write( "180-x=lbs of soybean meal needed\r \n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure crude protein before they are mixed together \n" ); document.write( "(0.065x+0.27*20+0.45(180-x)) has to equal the amount of pure crude protein after they are mixed together (0.15*200), so our equation to solve is:\r \n" ); document.write( "\n" ); document.write( "0.065x+0.27*20+0.45(180-x)=0.15*200 simplify \n" ); document.write( "0.065x+5.4+81-0.45x=30 collect like terms \n" ); document.write( "-0.385x+86.4=30 subtract 86.4 from each side \n" ); document.write( "-0.385x=-56.4 dibvide each side by -0.385 \n" ); document.write( "x=146.5------------------------lbs of corn needed \n" ); document.write( "20-----------------------------lbs of DDGs neede \n" ); document.write( "180-x=180-146.5=33.5-----------lbs of soybean meal needed\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "0.065*146.5 + 0.27*20 + 0.45*33.5=0.15*200 \n" ); document.write( "9.5225 + 5.4 + 15.075=30 \n" ); document.write( "~~~~30=30\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |