document.write( "Question 204911: Please help me find the solution to this problem:
\n" ); document.write( "Find the equation of a straight line through (-3,2) that is perpendicular to X+3y=6 with the equation in standard form.
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Algebra.Com's Answer #154677 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "x + 3y = 6 \r
\n" ); document.write( "\n" ); document.write( "3y = -x + 6\r
\n" ); document.write( "\n" ); document.write( "\"y+=+-%281%2F3%29x+%2B+2\" \r
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\n" ); document.write( "\n" ); document.write( "Since the equation of the line that passes through the point (-3, 2) is perpendicular to: \"y+=+-%281%2F3%29x+%2B+2\", then its slope is 3\r
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\n" ); document.write( "\n" ); document.write( "Therefore, using the point-slope formula: \"y-y%5B1%5D=m%28x-x%5B1%5D%29\", we get:\r
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\n" ); document.write( "y - 2 = 3(x - -3)\r
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\n" ); document.write( "\n" ); document.write( "y - 2 = 3x + 9\r
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%28y+=+3x+%2B+11%29\"
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