document.write( "Question 204911: Please help me find the solution to this problem:
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document.write( "Find the equation of a straight line through (-3,2) that is perpendicular to X+3y=6 with the equation in standard form. \n" );
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Algebra.Com's Answer #154677 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "x + 3y = 6 \r \n" ); document.write( "\n" ); document.write( "3y = -x + 6\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the equation of the line that passes through the point (-3, 2) is perpendicular to: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, using the point-slope formula: \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "y - 2 = 3(x - -3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y - 2 = 3x + 9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |