document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=204918>Question 204918</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diagonal of a square is 42.5 cm. Calculate the perimetre and area of the square. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #154670 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=154670\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     The diagonal of a square is 42.5 cm. Calculate the perimetre and area of the square.<BR>\n" );
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document.write( "Let x = length of one side of the square<BR>\n" );
document.write( "then from Pythagorean theorem we have:<BR>\n" );
document.write( "x^2 + x^2 = 42.5^2<BR>\n" );
document.write( "2x^2 = 1806.25<BR>\n" );
document.write( "x^2 = 903.125<BR>\n" );
document.write( "x = 30.052<BR>\n" );
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document.write( "Perimeter = 4x = 120.208 cm<BR>\n" );
document.write( "Area = x^2 = 903.125 sq cm\r<BR>\n" );
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