document.write( "Question 204912: Please can someone help me solve this problem:
\n" ); document.write( "Write the standard equation of the circle passing through (2,5) with the center at (-2,-3).
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Algebra.Com's Answer #154665 by nerdybill(7384)\"\" \"About 
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Write the standard equation of the circle passing through (2,5) with the center at (-2,-3).
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\n" ); document.write( "Equation of a circle:
\n" ); document.write( "(x-h)^2 + (y-k)^2 = r^2
\n" ); document.write( "where
\n" ); document.write( "(h,k) is the center
\n" ); document.write( "r is the radius
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\n" ); document.write( "The problem gives the center at (2,5)
\n" ); document.write( "Plugging that into our formula we have:
\n" ); document.write( "(x-2)^2 + (y-5)^2 = r^2
\n" ); document.write( "The only thing we need is the radius. Get this from the distance between (2,5) and (-2,-3):
\n" ); document.write( "d = sqrt[(x2-x1)^2 + (y2-y1)^2]
\n" ); document.write( "d = sqrt[(2+2)^2 + (5+3)^2]
\n" ); document.write( "d = sqrt[(4)^2 + (8)^2]
\n" ); document.write( "d = sqrt[16 + 64]
\n" ); document.write( "d = sqrt[100]
\n" ); document.write( "d = 10 (this is our radius)
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\n" ); document.write( "so now we finally get:
\n" ); document.write( "(x-2)^2 + (y-5)^2 = 10^2
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