document.write( "Question 204912: Please can someone help me solve this problem:
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document.write( "Write the standard equation of the circle passing through (2,5) with the center at (-2,-3). \n" );
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Algebra.Com's Answer #154665 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Write the standard equation of the circle passing through (2,5) with the center at (-2,-3). \n" ); document.write( ". \n" ); document.write( "Equation of a circle: \n" ); document.write( "(x-h)^2 + (y-k)^2 = r^2 \n" ); document.write( "where \n" ); document.write( "(h,k) is the center \n" ); document.write( "r is the radius \n" ); document.write( ". \n" ); document.write( "The problem gives the center at (2,5) \n" ); document.write( "Plugging that into our formula we have: \n" ); document.write( "(x-2)^2 + (y-5)^2 = r^2 \n" ); document.write( "The only thing we need is the radius. Get this from the distance between (2,5) and (-2,-3): \n" ); document.write( "d = sqrt[(x2-x1)^2 + (y2-y1)^2] \n" ); document.write( "d = sqrt[(2+2)^2 + (5+3)^2] \n" ); document.write( "d = sqrt[(4)^2 + (8)^2] \n" ); document.write( "d = sqrt[16 + 64] \n" ); document.write( "d = sqrt[100] \n" ); document.write( "d = 10 (this is our radius) \n" ); document.write( ". \n" ); document.write( "so now we finally get: \n" ); document.write( "(x-2)^2 + (y-5)^2 = 10^2 \n" ); document.write( " \n" ); document.write( " |